UNIVERSITY OF AGRICULTURAL SCIENCES, BANGALORE
Department of Genetics and Plant Breeding
GPB-21 Fundamentals of Plant Breeding (3+2+1)
II B.Sc. (Hons. Agri., C Section “C2” II Semester 2025-26
Practical exam
Department of Genetics and Plant Breeding
GPB-21 Fundamentals of Plant Breeding (3+2+1)
II B.Sc. (Hons. Agri., C Section “C2” II Semester 2025-26
Practical exam
Name: ___________________
ID. No: __________________
ID. No: __________________
Date: 25-06-2026
Max. marks: 15.00
Max. time: 1 Hour
Max. marks: 15.00
Max. time: 1 Hour
I. Fill in the blanks.
0.5 x 5 = 2.5
1.
Flowers having both stamens and pistil are called
flowers.
2.
Natural out-crossing in often cross-pollinated crops generally ranges
from to
%.
3.
Male sterility controlled by interaction of cytoplasmic and nuclear
genes is called male sterility.
4.
In maize, the female inflorescence is called
.
5.
Formula for percentage homozygosity after m generations of
selfing .
II. State True or false, if false correct them.
0.5 x 5 = 2.5
1.
Cleistogamy promotes self-pollination.
2.
Maize is a dioecious crop.
3.
Self-pollination increases homozygosity
in a population.
4.
Percentage of heterozygosity after
m generations of selfing (1/2)m x 100.
5.
A three way cross hybrid is produced by
crossing two double cross hybrids.
III. Match the following.
0.5 x 5 = 2.5
| Sl. No | A | B | |
|---|---|---|---|
| 1. | Cleistogamy | Ring method | |
| 2. | Entomophily | Protogyny | |
| 3. | Monoecious plant | Male and female flowers on the same plant | |
| 4. | Bajra | Transfer of pollen by insects | |
| 5. | Cotton | Self-pollination in unopened flowers |
IV. Answer any THREE.
1.5 x 3 = 4.5
1.
List any three tools present in a plant breeder's kit and mention
their uses.
2.
Define self-pollination and mention any two mechanisms promoting it.
3.
A breeder observed that a flower remains closed throughout anthesis.
What type of pollination is expected in such flowers? Explain.
4.
Differentiate between Genetic Male Sterility (GMS) and Cytoplasmic
Genetic Male Sterility (CGMS).
V. Answer any TWO.
1.5 x 2 = 3.0
1.
The Narrow Sense and Broad sense heritability of body weight in
mouse is 0.7. The Phenotypic variance (VP) is 0.6. What is the
additive genetic variance (VA) body weight in these mice?
2.
Predict the yield of all possible DCH from the SCH,
A x B = 8.8 q/ha,
B x D = 8.0 q/ha,
B x C = 9.2 q/ha,
A x D = 8.4 q/ha,
A x C = 8.9 q/ha,
C x D = 8.1 q/ha.
3.
How many single crosses (with reciprocal & without reciprocal)
can be made by using nine inbred lines?
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